27=13x^2

Solution for 27=13x^2 equation:

27=13x^2

We move all terms to the left:

27-(13x^2)=0

a = -13; b = 0; c = +27;
Δ = b2-4ac
Δ = 02-4·(-13)·27
Δ = 1404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1404}=\sqrt{36*39}=\sqrt{36}*\sqrt{39}=6\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{39}}{2*-13}=\frac{0-6\sqrt{39}}{-26}
=-\frac{6\sqrt{39}}{-26}
=-\frac{3\sqrt{39}}{-13}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{39}}{2*-13}=\frac{0+6\sqrt{39}}{-26}
=\frac{6\sqrt{39}}{-26}
=\frac{3\sqrt{39}}{-13}
$